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Scilla [17]
3 years ago
10

Y=-x+1 -2x-y=2 substitution

Mathematics
1 answer:
UNO [17]3 years ago
8 0

Step-by-step explanation:

y=-x+1 \\ -2x-y=2given

- 2x-( - x + 1)=2  \\  - 2x + x - 1 = 2 \\  - x = 2 + 1 \\  - x = 3 \\ x = 3

put x

-2( - 3)-y=2  \\ 6 - y = 2 \\  - y = 2 - 6 \\  - y =  - 4 \\ y = 4

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How do you solve #-\frac { a } { 8.06} + 7.02= 18.4#?
givi [52]
I see you're probably trying to use a math editor to present this problem.  Unfortunately, I'm unsure how to decipher your "-\frac {a }{8.06)."  What fraction are you speaking of?

Given "<span>#-\frac { a } { 8.06} + 7.02= 18.4#," all I can say with certainty is that you could legitimately subtract 7.02 from both sides:

</span><span>#-\frac { a } { 8.06} + 7.02= 18.4#
                              - 7.02  = -7.02
After I've heard back from you, I'll try to help you solve the entire problem.

</span>
5 0
4 years ago
PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP plzzzzzzzzzzzz example i do anything just help
Snowcat [4.5K]

Answer:

-9/20

(Decimal: -0.45)

Step-by-step explanation: 1/2 -1/4

                                             -2/5

                                       = 1/-5 -1/4

                                      =-1/5- 1/4

                                       = -1/5 +-1/4

                                      = -9/20

5 0
3 years ago
Decide whether the following two events are disjoint
OLga [1]
Brdfhjkjhgssdfhurdzcvnjfss
3 0
3 years ago
A student rewrote 5 (8 + 3) as
kotykmax [81]
It is D , 5 x 8 = 40, 5 x 3 = 15
7 0
2 years ago
Using an infinite geometric series for the repeating decimal 0.551¯¯¯¯¯¯¯¯, with ratio 11000, find integers a and b so that 0.55
irga5000 [103]

Answer:

Sum = 551/999

Where a = 551 and b = 999

The two integers are 551 and 999

Step-by-step explanation:

Given

Decimal = 0.551

Ratio = 1/1000

By repeating the decimal, we can write;

0.551 -bar = 0.551551551.....

0.551551551..... = 0.551 + 0.000551 + 0.000000551 + ....

= 551/1000 + 551/1000000 + 551/1000000000 + ......

= 551/10³ + 551/10^6 + 551/10^9 + .....

= n=0 Σ∝(551/10³)(1/10³)^n

Hence, the infinite geometrc series is Σ(551/10³)(1/10³)^n for n = 0 to

∝

Given the ratio of 1/1000

Let r = 1/1000

r = 1/10³

a = 551/10³

The sum is defined as follows;

a/(1-r)

Sum = 551/10³ / (1 - 1/10³)

Sum = 551/1000 ÷ 999/1000

Sum = 551/999

So, a/b = 551/999

Where a = 551 and b = 999

The two integers are 551 and 999

5 0
3 years ago
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