Answer:
$21.44
Explanation:
Calculation for the cost per equivalent unit for materials for the month in the first processing department
First step
Units completed and transferred out $7,500
Ending inventory($800+$8,400-$7,500)*70% Ending inventory =1,700*70%
Ending inventory =$1,190
Equivalent units for Materials $8,690
($7,500+$1,190)
Total materials costs $186,300
Second step
Cost per equivalent unit for materials=Total materials costs÷ Equivalent units for Materials
Cost per Equivalent unit for Materials $186,300÷$8,690
Cost per Equivalent unit for Materials=$21.44
Therefore the cost per equivalent unit for materials for the month in the first processing department is closest to $21.44
I would say 50, if im wrong im sorry
Answer:
Supplier or creditor ac Dr .... to Cash ac Cr
Explanation:
- Company records purchases using the gross method
Purchase ac Dr .. to Creditor ac Cr
{ Asset / Expense increase debit , liability increase credit }
- Paid supplier the amount owed from the August 1 purchase.
Supplier or creditor ac Dr .... to Cash ac Cr
{ Liability decrease debit , Asset decrease credit }
Answer:
- <u><em>Option B. $1,025 a month for 10 years.</em></u>
Explanation:
Calculate the present value of each option:
Formula:
![PV=C\times \bigg[\dfrac{1}{r}-\dfrac{1}{r(1+r)^t}\bigg]](https://tex.z-dn.net/?f=PV%3DC%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1%7D%7Br%7D-%5Cdfrac%7B1%7D%7Br%281%2Br%29%5Et%7D%5Cbigg%5D)
Where:
- PV is the present value of the constant monthly payments
- r is the monthly rate
- t is the number of moths
<u>1. Option A will provide $1,500 a month for 6 years. </u>
![PV=$\ 1,500\times \bigg[\dfrac{1}{(0.005\overline 6}-\dfrac{1}{0.005\overline 6(1+0.005\overline 6)^{(6\times12)}}\bigg]](https://tex.z-dn.net/?f=PV%3D%24%5C%201%2C500%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1%7D%7B%280.005%5Coverline%206%7D-%5Cdfrac%7B1%7D%7B0.005%5Coverline%206%281%2B0.005%5Coverline%206%29%5E%7B%286%5Ctimes12%29%7D%7D%5Cbigg%5D)
<u>2. Option B will pay $1,025 a month for 10 years. </u>
![PV=$\ 1,025\times \bigg[\dfrac{1}{(0.005\overline 6}-\dfrac{1}{0.005\overline 6(1+0.005\overline 6)^{(10\times12)}}\bigg]](https://tex.z-dn.net/?f=PV%3D%24%5C%201%2C025%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1%7D%7B%280.005%5Coverline%206%7D-%5Cdfrac%7B1%7D%7B0.005%5Coverline%206%281%2B0.005%5Coverline%206%29%5E%7B%2810%5Ctimes12%29%7D%7D%5Cbigg%5D)
<u>3. Option C offers $85,000 as a lump sum payment today. </u>
<u></u>
<h2 /><h2> Conclusion:</h2>
The present value of the<em> option B, $1,025 a month for 10 years</em>, has a the greatest present value, thus since he is only concerned with the <em>financial aspects of the offier</em>, this is the one he should select.
Answer and Explanation:
The computation of the maximum profit and the loss for the position is as follows:
Maximum profit is
= Call option strike price + Call price - Purchase price - Put price
= $54 + $0.85 - $45 - $0.85
= $9.00
And,
Maximum loss = - Purchase price - Put price + Put option strike price + Call price
= - $45 - $0.85 + $41 + $0.85
= - $4.00
We simply applied the above formula so that the correct value could come
And, the same is to be considered
