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Ede4ka [16]
3 years ago
13

One angle of the triangle is 4 times the second angle. The third angle of the triangle is 30 degrees more than the second angle.

find the measures of all the angles.
Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
X+4x+x+30=180
6x=150
X=25

So angles are 25, 100, 55 degrees
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icang [17]
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Don't forget to mark my anwer brainliest if I helped!
4 0
3 years ago
In the following equations <br>solve for x<br>2(x - 1) = 16<br>(3×1) - (5=86) -10​
lara31 [8.8K]

Step-by-step explanation:

2(X-1)=16

2X-2=16

2X=16+2

X=18÷2

X=9

I don't understand (3×1)-(5=86)-10

I think it is wrong or sth I don't know!

6 0
4 years ago
First derivative of <br>√{cosec2x).show with full step.​
Mice21 [21]

Answer:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

Step-by-step explanation:

we are given a derivative

\displaystyle \:  \frac{d}{dx} ( \sqrt{  \csc(2x) } )

and said to figure out the first derivative

to do so

recall chain rule:

\sf\displaystyle \:  \frac{d}{dx} (f(g(x)) =  \frac{d}{dg} (f(g(x)) \times  \frac{d}{dx} (g)

so we get

\displaystyle \: g(x) =  \csc(2x)

rewrite the derivative using the chain rule:

\displaystyle \:  \frac{d}{dg} ( \sqrt{  g } )  \times  \frac{d}{dx} ( \csc(2x) )

use square root derivative rule to simplify:

\displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dx} ( \csc(2x) )

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dn}( \csc(n) ) \times  \frac{d}{dx} (2x)

use derivative formula to simplify derivatives:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - \cot(n)   \csc(n)  \times  2

substitute the value of n:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - 2\cot(2x)   \csc(2x)

substitute the value of g:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2\cot(2x)   \csc(2x)

now we need our trigonometric skills to simplify

rewrite cot and csc:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2 \dfrac{ \cos(2x) }{ \sin(2x) }   \dfrac{1}{ \sin(2x) }

simplify multiplication:

\sf \displaystyle \:   \frac{1}{ \cancel{ \:  2}\sqrt{ \csc(2x) } }  \times    \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }

simplify multiplication:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

4 0
3 years ago
Read 2 more answers
Plzzzzzz answerrrrrr asapppppppp<br> ******will mark brainliest *******
brilliants [131]

The first option is the correct answer

5 0
4 years ago
What is greater than 3:5
andriy [413]

Answer:

They have a common numerator, that is 3. Therefore we can directly conclude that fraction with smaller denominator is greater of the two. Thus 3/5 is greater than 3/6. One way to compare the two fractions would be to both have the same denominator, so that numerators will be easily compared

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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