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soldier1979 [14.2K]
3 years ago
7

9/47

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0

Which is the number of boys and girls? Are boys 9 and girls 47?

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In the bridge below , AABC~AXYZ.If AB=AC=25 feet,BC=20 feet,and YZ=10 feet, then what is XZ?
labwork [276]

Answer:

I think It's A).25 ft.

Step-by-step explanation:

I d k if I'm right but I tried btw I hope it helps

BRAINLEST PLZZZZZZZZ?

6 0
2 years ago
Can anyone help me solve these please
pickupchik [31]
R^2+(ab)^2= (ao)^2
ab=6
ao=11.7

Plug in

r^2+6^2=11.7^2

simplify

r^2+36= 136.89
-36 both sides

r^2=100.89
square root both sides

r= 10.04 rounded 10
6 0
3 years ago
You want to estimate the number of students in your middle school school who buy school lunch. Which sample is unbiased?
Nezavi [6.7K]
A biased example: Asking students who are in line to buy lunch 

An unbiased example: Asking students who are leaving/going to lunch(<em>NOT buying </em><em>lunch</em><em />).

But in this case, the answer choices can be... confusing.
Don't panic! You're given numbers and, of course, your use of logic.

Answer choice A: 100 students grades 6-8
Answer choice B: 20-30 students any <em>one</em> grade<em></em><em>
</em>Answer choice C: 5 students
<em></em>Answer choice D: 50 students grade 8

An unbiased example would be to choose students from <em>any grade.</em> So we can eliminate choices B and D.

Now, the question wants to <em>estimate how many people at your middle school buy lunch.</em> This includes the whole entire school, and if you are going to be asking people, you aren't just going to assume that if 5 people out of 5 people you asked bought lunch, the whole school buys lunch.

So, to eliminate all bias and/or error by prediction, answer choice A, the most number of students, is your answer.

6 0
3 years ago
Have 5 pieces of candy and 29 people. How many pieces are the candy divided into for everyone to get a piece.
Ivanshal [37]

Answer:

everyone gets 5 pieces and the rest gets thrown out

Step-by-step explanation:

29/5=5.8

but obviously ur not gonna break the candy into .8 so everyone just gets 5 so its even

8 0
4 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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