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musickatia [10]
3 years ago
7

Allie sold oatmeal cookies at a stand for two days. She made 35.20 on the first day. She used 1/4 of this money to buy more supp

lies for the next day. How much money did Allie use to buy more supplies for the next day
Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0
Multiply the money earned on the first day ($35.20) by 1/4.

= 35.20 * 1/4
multiply numerators

= (35.20 * 1)/4

=35.20/4
divide

= $8.80


ANSWER: $8.80 was used to buy more supplies

Hope this helps!  :)
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One student can paint a wall in 16 minutes. Another student can paint the same wall in 24 minutes. Working together, about how l
Mazyrski [523]
Let's look at work rates per minute.

Together they can paint the wall in x minutes.
Working together, in 1 minute, they do 1/x of the job.

The student who paints the wall in 16 minutes does 1/16 of the job in 1 minute.
The student who paints the wall in 24 minutes does 1/24 of the job in 1 minute.
Together, they do 1/16 + 1/24 of the job in 1 minute, but from above, we see that together, they do 1/x of the job in 1 minute, so 1/16 + 1/24 must equal 1/x. That gives us our equation.

1/16 + 1/24 = 1/x

1/16 * 3/3 + 1/24 * 2/2 = 1/x

3/48 + 2/48 = 1/x

5/48 = 1/x

x = 48/5 = 9.6

Answer: It takes them 9.6 minutes, or about 10 minutes to do the job together.


5 0
3 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\
(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
Read 2 more answers
Solve the quadratic equation by completing the square.
Step2247 [10]

Answer:

x1, x2 = 4.74 , -2.74

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 2x - 13

a = 1     b = -2    c = -13

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1

x1 = (2 + √ (4 + 52)) / 2

x1 = (2 + √ 56 ) / 2

x1 = (2 + 7.48) / 2

x1 = 9.48 / 2

x1 = 4.74

x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1

x2 = (2 - √ (4 + 52)) / 2

x2 = (2 - √ 56 ) / 2

x2 = (2 - 7.48) / 2

x2 = -5.48 / 2

x2 = -2.74

6 0
3 years ago
Please help meee! :< An author receives $0.60 for each hardcover book or paperback book that is sold. There were x hardcover
rusak2 [61]
D) 47,000

0.60 (<em>x</em>+38,000)= 51,000
(0.60<em>x</em>)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000
5 0
3 years ago
What are the factors of 36
nasty-shy [4]
1,36. 2,18. 3,12. 4,9. 6,6. I thibk thats all
4 0
3 years ago
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