Answer:
x^2-2x-4=0
Δ=2^2-4*1*(-4)
Δ=4+16=20
VΔ=2V5
x1= (2+2V5)/2=1+V5
the answer is D
Step-by-step explanation:
Answer:
41
Step-by-step explanation:
So basically you need to use the pythagorean thrm. Essentially, the diagonal and the width and length create a triangle, the diagonal being the hypothenuse. So the formula goes as ![\sqrt[]{a^{2} +b^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Ba%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%7D)
. the variable "a" being the length and the variable "b" being the width. So plug it in and there you have your answer!
Step-by-step explanation:
-8.0-(-0.4+0.6)÷2
= -0.8-(0.2)÷2
= -0.8 -0.2 ÷2
= -0.9
use Bodmas method
Answer:
(B)
Step-by-step explanation:
we know that standard equation of parabola y²= 4x or x² = 4y .
So option (B) is correct .
Hope it's helpful
