1st step. Calculate the area of the parallelogram
We can use the following formula:

where,
base, b = 9 km
height, h = 5 km
Therefore,

The area of the parallelogram is 45 km^2
2nd step. Calculate the area of the triangle
Let's use this formula:

where,
base, b = 6 km
height, h = 3 km
Therefore,

The area of the triangle is 9 km^2
3rd step. calculates the ratio of the area of the parallelogram to the area of the triangle

Answer: the area of the parallelogram is 5 times greater than the area of the triangle.

Taking the square root of both sides gives two possible cases,

or

Recall that

If
and
, we have

so in the equations above, we can write

Then in the first case,


(where
is any integer)


and in the second,




Then the solutions that fall in the interval
are

Answer:
Might be
Step-by-step explanation:
A.) The probability of all dependent events can be calculated using the OR formula
3 reds in the 10 remaining cards
so that is 30% are red
Answer:
Attach it plz or I can't help
Step-by-step explanation: