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2 years ago

God Bless u plz help plz bless ur grades

Mathematics

1 answer:

expeople1 [14]2 years ago

3 0

$g(x)=-9^x-5$

So, Option A is correct option.

Step-by-step explanation:

We are given function $f(x)= 9^x$

We need to find transformation g(x)

if f(x) is reflected on x-axis and a vertical translation 5 units down.

Finding the transformation:

if f(x) is reflected on x-axis

then g(x) will be - f(x) i.e

$g(x)=-9^x$

a vertical translation 5 units down.

Then g(x) will be f(x)-5

So,

$g(x)=-9^x-5$

So, Option A is correct option.

Keywords: Transformations

Learn more about Transformations at:

#learnwithBrainly

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What are all the parts of an algebraic expression and can you define them?

mr Goodwill [35]

Variables - a quantity that may change, depends on the context of the math problem. Ex: x,y
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3 years ago

What is the midpoint of (2,-2,4) and (-2,0,6)

Mekhanik [1.2K]

Midpoint of (a,b,c) and (e,f,g) is
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just average them

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3 years ago

Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

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...

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