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inysia [295]
3 years ago
10

Un tanque de almacenamiento de agua instalado en una comunidad tiene forma de prisma rectangular y una capacidad de 8 000 litros

, su base mide 2.5 m por 2 m. ¿Qué altura tiene este tanque? ¿Qué cantidad de agua contendría si sólo llegara el agua a una altura de 75 cm?
Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

a) la altura es de 1.6 metros

b) contendría 3750 litros

Step-by-step explanation:

1000 litros = 1m³

8000 litros = 8000/1000 = 8m³

La formula del volumen de un prisma rectangular es:

v = área de la base * altura

el área de la base es:

ab = 2.5m * 2m = 5m²

entonces:

v = 5 * altura

v = 8m³

así que:

8m³ = 5m²* altura

altura = 8m³/5m²

altura = 1.6 metros

  • Si la altura fuese de 75cm

1 metro = 100 centímetros

75 cms = 75/100 = 0.75 metros

entonces:

volumen = 5m² * 0.75m

volumen = 3.75m³

3.75m³ = 3.75*1000 = 3750 litros

El agua que contendría sería de:

3750 litros

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Answer:

<h2>b = 15°</h2>

Step-by-step explanation:

If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.

We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:

m∠QPR + m∠PRQ + m∠RQP = 180°

We have

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Therefore

2(m∠QPR) + 60° = 180°       <em>subtract 60° from both sides</em>

2(m∠QPR) = 120°           <em>divide both sides by 2</em>

m∠QPR = 60° and m∠PRQ = 60°

Therefore ΔPRQ is equaliteral.

ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore

m∠SPR = m∠PRS

In ΔAPS we have:

m∠SPR + m∠PRS + m∠RSP = 180°

2(m∠SPR) + 90° = 180°            <em>subtract 90° from both sides</em>

2(m∠SPR) = 90°             <em>divide both sides by 2</em>

m∠SPR = 45° and m∠PRS = 45°

m∠PRQ = m∠PRS + b

Susbtitute:

60° = 45° + b           <em>subtract 45° from both sides</em>

15° = b

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