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3 years ago

One third 1 3 as a decimal rounded to the nearest hundredth.

1 answer:

7 0

4.33333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333repeating

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A metal plate is 8.431 centimeters wide. Which is this measure written in word form?

vagabundo [1.1K]

Answer:

Eight and one hundred thirty-four thousandths

Step-by-step explanation:

Thats how u write it in word form! i hope this helped :)

6 0

3 years ago

Mark the statements that are true.

lara [203]

Answer:

Correct answers:

A. An angle that measures $\frac{\pi}{6}$ radians also measures $30^o$

C. An angle that measures $180^o$ also measures $\pi$ radians

Step-by-step explanation:

Recall the formula to transform radians to degrees and vice-versa:

$\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\ \\\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians$

Therefore we can investigate each of the statements, and find that when we have a $\frac{\pi}{6}$ radians angle, then its degree formula becomes:

$\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians\\\angle\,degrees=\frac{180^o}{\pi} \,* \,\frac{\pi}{6} \\\angle\,degrees=\frac{180^o}{6} \\\angle\,degrees=30^o$

also when an angle measures $180^o$ , its radian measure is:

$\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\\angle\,radians=\frac{\pi}{180^o} \,* \,180^o\\\angle\,radians=\pi$

The other relationships are not true as per the conversion formulas

7 0

3 years ago

Expressions equivalent to 6x+4

stiv31 [10]

2(3x+2) I couldn’t find any other ones, your best bet would be to go into decimals or fractions if you want to find more.

6 0

3 years ago

Pls solve part b) iii thanks

Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees