Answer: y = (x +2)² + 5
<u>Step-by-step explanation:</u>
y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>
Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)
y = a(x - h)² + k
9 = a(0 - (-2))² + 5
9 = a(0 + 2)² + 5
9 = a(2)² + 5
<u>-5 </u> <u> -5 </u>
4 = a(4)
<u>÷4 </u> <u> ÷4 </u>
1 = a
Next, plug in "a" and the vertex (h, k):
y = a(x - h)² + k
y = 1(x +2)² + 5
y = (x +2)² + 5
The slope is 2x and the y intercept is 5
The slope is positive
Plug in the known x value
2(-1/2)-3y=6
-1-3y=6
-3y=7
y=-7/3
Final answer: -7/3
Differentiation is part of calculus
differentiation basically allows you to find the gradient of tangent
