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Naddik [55]
3 years ago
12

3x^+5x+2=0

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0

Answer:

  • See below

Step-by-step explanation:

<u>Given equation:</u>

  • 3x² + 5x + 2 = 0

<u>Factorize it in steps:</u>

  • 3x² + 5x + 2 = 0
  • 3x² + 3x + 2x + 2 = 0
  • 3x(x + 1) + 2(x + 1) = 0
  • (x + 1)(3x + 2) = 0

<u>The roots are:</u>

  • x + 1 = 0 ⇒ x = - 1
  • 3x + 2 = 0 ⇒ 3x = - 2 ⇒ x = - 2/3
Kryger [21]3 years ago
4 0

\\ \tt\hookrightarrow 3x^2+5x+2=0

  • Split the middle term

\\ \tt\hookrightarrow 3x^2+3x+2x+2=0

  • Take commons

\\ \tt\hookrightarrow 3x(x+1)+2(x+1)=0

\\ \tt\hookrightarrow (3x+2)(x+1)=0

\\ \tt\hookrightarrow x=\dfrac{-2}{3}\:or\:x=-1

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The length of a flower petal is 600 millimeters. The stem of the flower is 10
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6000 millimeters.

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2x-5y=9<br> 3x+4y=2<br> solve the simultaneous equations
wariber [46]

\huge\boxed{x=2;\ y=-1}

\left\{{{2x-5y=9}\atop{3x+4y=2}}\right

First, we will solve the second equation for x. Subtract 4y from both sides of the second equation.

3x=2-4y

Divide both sides of the second equation by 3.

x=\frac{2}{3}-\frac{4}{3}y

\left\{{{2x-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

Substitute the value of x from the second equation into the first.

\left\{{{2(\frac{2}{3}-\frac{4}{3}y)-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

2(\frac{2}{3}-\frac{4}{3}y)-5y=9

We will solve the first equation for y.

Distribute the 2 to the (\frac{2}{3}-\frac{4}{3}y).

\frac{4}{3}-\frac{8}{3}y-5y=9

Combine the like terms.

\frac{4}{3}-\frac{23}{3}y=9

Add \frac{4}{3} on both sides.

-\frac{23}{3}y=9-\frac{4}{3}

-\frac{23}{3}y=\frac{23}{3}

Divide both sides by \frac{23}{3}.

-y=1

Multiply both sides by -1.

y=\boxed{-1}

Substitute the value of y into the second equation.

\left\{{{y=-1}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

x=\frac{2}{3}-\frac{4}{3}*-1

Multiply.

x=\frac{2}{3}+\frac{4}{3}

Add.

x=\frac{6}{3}

x=\boxed{2}

5 0
3 years ago
Read 2 more answers
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