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Dmitry [639]
3 years ago
7

The ratio 8.4 to 4.4

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0
Ratios can be written in multiple ways such as

a:b
a to b
a/b

So we can write yours in those three ways:

8.4:4.4
8.4 to 4.4
8.4/4.4
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What is the solution to log Subscript 3 Baseline (x + 12) = log Subscript 3 Baseline (5 x)
jonny [76]

I hope this helps you

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3 years ago
Please help asap!!!! 53 points!
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The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
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8 0
3 years ago
Read 2 more answers
Need help with all of these!!! ASAP!!<br><br> 15, 16, 17, 18!!!
vodomira [7]

Answer:

15. A

16. B

17. B

18. C

Step-by-step explanation:

8 0
3 years ago
The temperature in the desert can
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4 0
3 years ago
High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
zalisa [80]

Answer:

The students have to score 0.74 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

A random variable <em>X</em> is said to have a normal distribution with parameters <em>µ</em>    (mean) and <em>σ</em>² (variance).

If X \sim N (\mu, \sigma^{2}), then z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.

Let <em>X</em>  be defined as the scores of students at the National Financial Capability Challenge Exam.

It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.

That is, P (X > x) = 0.23.

⇒ P(\frac{X-\mu}{\sigma}>\frac{x-\mu}{\sigma})=0.23

⇒

   P(Z>z)=0.23\\1-P(Z

The value of <em>z</em> for this probability value is:

<em>z</em> = 0.74.

*Use a <em>z</em>-table.

Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.

8 0
3 years ago
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