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Mariulka [41]
4 years ago
15

Find the hypotenuse for the following ​

Mathematics
2 answers:
masya89 [10]4 years ago
6 0

Answer:

6.403 units

or \sqrt{41}

Step-by-step explanation:

We want the hypotenuse.

The hypotenuse is from the point (-3, -1) to point  (2, 3)

D( (-3, -1), (2, 3)) = root ( (2 - (-3))^2 + (3 - -1)^2 ) =

D( (-3, -1), (2, 3)) = root ( 5^2 + 4^2)  =  root( 25 + 16)

D( (-3, -1), (2, 3)) = root ( 41)

D( (-3, -1), (2, 3)) = 6.403 units

-BARSIC- [3]4 years ago
4 0

Answer:

6.4 (rounded to nearest tenth)

Step-by-step explanation:

Distance from (-3,-1) to (2,-1) is 5 units

Distance from (2,-1) to (2,3) is 4 units

4^2+5^2=x^2     x=hypothenuse

16+25=x^2

41+x^2

(take square root of both sides)

x=6.4

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Answer:

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Step-by-step explanation:

we know that

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(-2\frac{1}{2},-3)\ and\ (1,-3)

Convert mixed number to an improper fraction

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so

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substitute the values in the formula

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Convert to mixed number

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B40%20%7Bx%7D%5E%7B8%7D%20%7By%7D%5E%7B12%7D%20%20%7D%20" id="TexFormula1"
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