All categories

3 years ago

Please help with the plotting and the problems themselves

Mathematics

1 answer:

liberstina [14]3 years ago

3 0

The first pic is d : and the solution is undefined because both lines don't intersect

the second both equation represent the same line

You might be interested in

the RATIO of floor seats to balcony seats in a theaters is 20:1. does this theater have more floor seats or more balcony seats?

GalinKa [24]

Yes, this theater has more floor seats than balcony seats simply because of the ratio. Your answer is actually in the question. For example, if you have 100 floor seats, then according to the ratio you should only have 5 balcony seats. So yes, there are more floor seats than balcony seats.

3 0

3 years ago

The ratio of adult tickets sold to child tickets sold was 3:2, how many<br> child tickets were sold?

Makovka662 [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I need help ASAP please. It's a contest

igor_vitrenko [27]

Answer:

3.25

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

4 years ago

Please answer this question correctly for 25 points and brainliest!!

lesya692 [45]

Step-by-step answer:

Given an enlargement from preimage (ABC) to image (A'B'C').

Need to find scale factor.

Solution:

Scale factor = linear size of image / linear size of preimage.

From the accompanying diagram, we see that

L(preimage) = AC = 4 units

L(image) = A'C' = 12 units

Therefore

Scale factor = L(image) / L(preimage) = 12 / 4 = 3

4 0

3 years ago