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AleksAgata [21]
3 years ago
6

A 450m long field is drawn to a scale 1cm to 90cm.find the lenth of drawing​

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

5 cm

Step-by-step explanation:

The length of the drawing will be 450 / 90 = 5 cm.

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Answer:

x = 27

Step-by-step explanation:

Given

The attached figure

Required

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So:

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x = 135/5

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kicyunya [14]

Answer:

<h2>               XN = 6</h2>

Step-by-step explanation:

If XY is bisector of angle AXN then:   \dfrac{YN}{AY}=\dfrac{XN}{AX}

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8 0
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Triangle F G E is shown. Angle F E G is a right angle. The length of hypotenuse F G is 18.6 inches and the length of F E is 12 i
Delicious77 [7]

Answer:

Measure of ∠FGE is 40.2°.

Step-by-step explanation:

Refer to the attachment.

Consider ΔFGE. Given that ∠FEG = 90° and ∠FGE is x°.

To find the value of ∠FGE use trigonometric ratios.

Use sine ratio to find the value of ∠FGE.

\sin \theta=\dfrac{opposite\:side}{hypotenuse\:side}

Rewriting it in terms of x° as follows,

\sin x=\dfrac{opposite\:side}{hypotenuse\:side}

Now find the opposite and hypotenuse side of the angle ∠FGE.

So opposite side of ∠FGE is FE and hypotenuse side of ∠FGE is FG.

Substituting the values,

\sin x=\dfrac{FE}{FG}

Given that length of FE is 12 inch and FG is 18.6 inch.

Substituting the value,

\sin x=\dfrac{12}{18.6}

To find the value of x, taking inverse sin.

x=\arcsin \left(\dfrac{12}{18.6}\right)

Calculating the value,

x=40.17

Rounding to nearest tenth the value of angle is 40.2

Therefore measure of ∠FGE is 40.2° .

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