Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, 
⊥ 
, AP = 9, and PM = 16
² + 
² = ²
= 
+ PM = 9 + 16 = 25
= 25
² = ² + ² = 9² + ²
∴ ² = 9² + ²
Similarly we get;
² = 16² + ²
Therefore, we get;
² + ² = 9² + ² + 16² + ² = ² = 25²
2·² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From ² = 9² + ², we get
= √(9² + 12²) = 15
= 15
From, ² = 16² + ², we get;
= √(16² + 12²) = 20
= 20.
Step-by-step explanation:
angle HIJ=107°
angle IDJ=31°
now,
angle HIJ+angle JID=180°{ being straight angle}
107+angle JID=180°
angle JID=180°-107=73°
again,
angle JID+angleIDJ+angleDJI=180°{ sum of angle of triangle}
73°+31°+angleDJI=180°
angle DJI=180°-1104°=76°
hence,
angleAJF=angleDJI{ vertically opposite angle}
x=76°
hope it helps.
You find out what you have to do to get three then one and so on
Answer:
you can do it bubu amp tanga
