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Arada [10]
3 years ago
7

D%20%20%5Ctimes%20%20%7B15x%7D%5E%7B5%7D%20" id="TexFormula1" title=" {3x}^{3} \times 4 {y}^{5} \div {8y}^{2} \times {15x}^{5} " alt=" {3x}^{3} \times 4 {y}^{5} \div {8y}^{2} \times {15x}^{5} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
garik1379 [7]3 years ago
6 0
The answer is 12x3y5 divided by 8x15x5y2
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Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H

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