<img src="https://tex.z-dn.net/?f=%20%7B3x%7D%5E%7B3%7D%20%20%5Ctimes%204%20%7By%7D%5E%7B5%7D%20%20%5Cdiv%20%20%7B8y%7D%5E%7B2%7

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3 years ago

D%20%20%5Ctimes%20%20%7B15x%7D%5E%7B5%7D%20" id="TexFormula1" title=" {3x}^{3} \times 4 {y}^{5} \div {8y}^{2} \times {15x}^{5} " alt=" {3x}^{3} \times 4 {y}^{5} \div {8y}^{2} \times {15x}^{5} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

garik1379 [7]3 years ago

6 0

The answer is 12x3y5 divided by 8x15x5y2

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5x-2>8 does x equal >2

katovenus [111]

Yes that it correct

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2 years ago

Read 2 more answers

Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago

In febuary, john has $1000 in his account. in may, he had 2600. what is the rate of change?

sergiy2304 [10]

Answer:

866.7 each month

Step-by-step explanation:

what you would do is count how many months are in between which is 3 and then you would divide 2600 by 3 and get 866.7 so the rate of change is 866.7 each month

please mark brainliest

5 0

2 years ago

How to solve by elimination

natka813 [3]

How to solve with elimination: with the equations on the top, add the number on top and bottom if they share a variable such as x. do the rest for all of the numbers.

5 0

3 years ago

Rhion sat maths and English test

Sauron [17]

Answer:

Rhion did better in maths test.

Step-by-step explanation:

Given that:

Rhion scored 14 out of 17.

We will find percentage and then compare them.

Percentage = $\frac{Score}{Total\ marks}*100$

Percentage = $\frac{14}{17}*100$

Percentage = 82.35%

Rhion scored 31 out of 39.

Percentage = $\frac{31}{39}*100$

Percentage = 79.48

On comparing,

82.35 > 79.48

Hence,

Rhion did better in maths test.

4 0

2 years ago