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just olya [345]
3 years ago
14

HELP , ILL GIVE BRAINLIEST. Answer 5-8 please .

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

#5. 17, #6. 22, #7. 14, and #8. 13

Step-by-step explanation:

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I NEED AN ANSWER ASAP PLZZZ!!!
Helen [10]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A survey of 100 high school students provided this
HACTEHA [7]

Answer:

35/100

Step-by-step explanation:

You have to find how many juniors there are, so if you add 13, 20, and 2 you get 35. For the denominator you have to find the total number of students, so just add all of the numbers together to get 100. So there is a 35/100 chance that a randomly selected student is a junior.

5 0
1 year ago
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
Need some help please
aliina [53]

Answer:

the answer is 12 attendees

Step-by-step explanation:

Let a=the attendees & Let d=the cost

if the budget is $97 and the cost of the gala is represented by the equation d=7a+13, substitute the $97 for d

d=7a+13

97=7a+13

now take subtract 13 from both sides

97-13=7a+13-13

since the 13 cancels out on the right side it'll now read:

84=7a

to get a by itself you now divide 7 from both sides getting a by itself

84/7=7a/7

12=a

so the answer will be 12


3 0
3 years ago
Jane received a $50.00 gift card for a photo center. She used it to buy prints that cost 15 cents each. The remaining balance, B
vlabodo [156]
Answer: $37

Step-by-step explanation:
The remaining balance, B (in dollars), on the card after buying x prints is given as $50.00 - 0.15x.


Therefore, the remaining balance on the card if Jane bought 20 prints will be:
= $50.00 - 0.15x.
= $50.00 - 0.15(20)
= $50.00 - $3.00
= $47.00

7 0
2 years ago
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