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vovikov84 [41]
3 years ago
15

I buy a 5 kg jar of sweets for £25. Then i divide the sweets into 125g packets and sell them for 99p each​

Mathematics
1 answer:
kotegsom [21]3 years ago
3 0

Answer:

is that the whole question? it looks unfinished to me-

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Translate this phrase into an algebraic expression.
Verizon [17]

Answer:

Step-by-step explanation:

9n-2

5 0
3 years ago
Find the equation for the line that passes through the point (−2,0), and that is perpendicular to the line with the equation 2/3
patriot [66]

Answer:

y = 3/2 x + 3

Step-by-step explanation:

2/3 x + y = -14/3

y = -2/3 x − 14/3

The slope of this line is -2/3.  So the perpendicular slope is the opposite of the inverse:

m = -1 / (-2/3)

m = 3/2

We know the slope of the line and a point on the line, so using point-slope form:

y − 0 = 3/2 (x − (-2))

Simplifying into slope-intercept form:

y = 3/2 (x + 2)

y = 3/2 x + 3

5 0
3 years ago
I need help please????
mezya [45]

Answer:

112

Step-by-step explanation:

Just solve it easy peasy

7[(25+9)-3(2-1)]

First solve the inner brackets

7[(34)-3(3)]\\7[25-9]

Now the other brackets

7[25-9]\\7[16]\\112

5 0
3 years ago
Read 2 more answers
Find the co-ordinate of the image of the point A (3, -2) when it is reflected on the line x=0 and then rotated about origin thro
Luba_88 [7]

Answer:

Step-by-step explanation:

Rotations are easy when its multiples of 90 degrees; 90,180,270,360. Treat them like they’re a complex number like [x+yi]*i=[-y,xi] so rotating by 90 degrees and 180 is i squared [-1]! So [-3,2] rot90 is [-2,-3].

Reflection about the y=x line is change places. [x.y]=[y,x].

So [-2.-3] reflected about the y=x line is [-2.-3]=[-3.-2],

Compile a list of these transform is best practice technique in this area.

5 0
3 years ago
The first two terms of a sequence are 5 and 7. Each term after the second is found by taking the average (arithmetic mean) of al
ch4aika [34]

Answer:

6

Step-by-step explanation:

We can prove that every number after the second will be a six by induction.

<em>Base case.</em> Since \frac{5 + 7}{2} = 6, so the third term is a six.

<em>Inductive hypothesis</em>. Fix the number of terms to be <em>n</em> and assume that

\frac{1}{n} \sum\limits_{i=1}^{n}t_i = 6

<em>Inductive step</em>. We will now show that \frac{1}{n+1} \sum\limits_{i=1}^{n+1}t_i = 6.

Notice that

$\begin{array}{lll}\frac{1}{n+1} \sum\limits_{i=1}^{n+1}t_i & = \frac{n}{n(n+1)} \sum\limits_{i=1}^{n+1}t_i & \\& = \frac{t_{n+1}}{n+1} + \frac{n}{n(n+1)} \sum\limits_{i=1}^{n}t_i &\\& = \frac{t_{n+1}}{n+1} + \frac{6n}{n+1} & \text{(by the IH)}\\& = \frac{6}{n+1} + \frac{6n}{n+1} & \text{by de\\finition}\\& = \frac{6(n+1)}{n+1} & \\& = 6 & \end{array} \square$

6 0
3 years ago
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