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34kurt
3 years ago
14

What is the approximate length of the diameter, d? *

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

C) 250 feet

Step-by-step explanation:

Let the diameter of the circle be d feet.

\therefore \: C = \pi d \\   \therefore \: 250\pi = \pi d \\   d =  \frac{250\pi}{\pi}  \\ d = 250 \: ft

Finger [1]3 years ago
7 0
A/125 I think hopefully that’s Rt
You might be interested in
50 ft
juin [17]

9514 1404 393

Answer:

  1725 ft²

Step-by-step explanation:

The formula for the area of a trapezoid is ...

  A = 1/2(b1 +b2)h

Here, the bases are given as 65 ft and 50 ft, and the height is 30 ft. Then the area is ...

  A = 1/2(65 ft +50 ft)(30 ft) = (1/2)(115 ft)(30 ft) = 1725 ft²

You tell the salesman your lawn area is 1725 square feet.

5 0
3 years ago
QUESTION 20
atroni [7]

.Answer:

The answer is below

Step-by-step explanation:

The patient loses 1 kg every week for 5 weeks.

1 kg = 2.2 lbs

Therefore the patient loses 2.2 lbs every week for 5 weeks.

a) The weight of the patient after 5 weeks = 245 lbs. - (5 weeks)(2.2 lbs per week)

The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

b) The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

1 kg = 2.2 lbs.

234 lbs. = 234 lbs. * 1 kg per 2.2 lbs. = 106.36 kg

7 0
3 years ago
-(7p+6)-2(-1-2p)<br> what is that simplified?
charle [14.2K]

Answer:

-3p-40

Step-by-step explanation:

-(7p+6)-2(-1-2p)

-7p-42+2+4p

-3p-40

4 0
3 years ago
6÷2(1+2)=?
mina [271]
I don't have the answer for the second one, but the answer to number 1 is 9.

6÷2(1 + 2) =

6÷2(3) =

3(3) =

9
5 0
3 years ago
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
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