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4 years ago

6

PLEASE I NEED HELP WITH MY MATHS ANGLES HOMEOWRK

1 answer:

alekssr [168]4 years ago

8 0

Answer:

that is the solution to the 2nd question

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TRUE OR FALSE <br>becomes zero for x=1<br>PLEASE HELP

harkovskaia [24]

True hope this helps

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3 years ago

A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.64 years and the standard deviation i

____ [38]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

Assuming that conditions have been met for the interval, we use the formula $\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}$ where $\bar{x}$ represents the sample mean, $t$ represents the critical value, $s$ represents the sample standard deviation, and $n$ is the sample size.

The critical value of $t$ for an 80% confidence level with degrees of freedom $df=n-1=25-1=24$ is equivalent to $t=1.317836$

Thus, we can compute the confidence interval:

$\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}\\\\CI=32.64\pm1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\\\\CI\approx\{30.17,35.11\}$

Therefore, we are 80% confident that the true mean age of all customers is between 30.17 and 35.11 years.

<u>Part B</u>

The margin of error is $\displaystyle t\frac{s}{\sqrt{n}}=1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\approx2.47$

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2 years ago

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maw [93]

Answer:where are the options ???

Step-by-step explanation:

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2 years ago

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3 years ago

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balandron [24]

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Step-by-step explanation:

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