$\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)$

3 0

3 years ago

What is the value of x? Enter your answer in the box. mm Triangle V T K with segment T Y such that Y is on segment V K, between

lapo4ka [179]

Answer:

VK = x = 98 mm

Step-by-step explanation:

TY is the bisector of angle T, so it divides segments of the triangle proportionally. That is, ...

VY/VT = KY/KT

VY = VT·KY/KT = (57 mm)·68/192.2 = 30 mm

Then

VK = VY + YK = 30 mm + 68 mm

VK = 98 mm

5 0

3 years ago

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ZB= I Round your answer to the nearest hundredth. A 5 ? B

zalisa [80]

Answer:

∠B = 36.87

Step-by-step explanation:

Since you are trying to find the angle measurement, you must use the inverse of cosine: $cos^{-1}$ (you're using cosine because you have the opposite side and adjacent side):

$cos^-1(4/5)$

≈36.87

5 0

3 years ago

Consider the two functions given below. What is the y-intercept of g? A. (0,4) B. (0,14) C. (0,-5) D. (0,9)

NISA [10]

(0,4) this si the answer

7 0

3 years ago

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