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sammy [17]
3 years ago
13

A phone company charges a monthly fee of $35.00 and $0.10 per text message. Bridget wants to pay less than $1200.00 total for he

r monthly phone bill over a 12-month period. What is the most number of text she can send to stay within her budget for the year? Question 11 options: 11,650 11,649 7,800 7,799
Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
I believe the answer to your question is 11650
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Which graph represents the solution set for the system 6x + y > -3 and 2x + y ≤ 4?
VikaD [51]
This one.

The doubly-shaded area is the solution set. The dashed line is not included.

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3 years ago
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Cody said that dividing a unit fraction by a whole number is the same as multiplying the unit fractions by a unit fraction with
LekaFEV [45]

Answer:

True

Step-by-step explanation:

Hi, the statement is true, because to divide a fraction we have to turn the second fraction upside down and multiply them. Since a whole number x can be written as x/1, it also applies to the case of dividing a fraction by a whole number.

We can prove it with an example.

Dividing a unit fraction by a whole number  

1/2 ÷ 2 = (1x1) / (2x2) = 1/4

Multiplying the unit fractions by a unit fraction with a whole number as a denominator

1/2 x 1/2= (1x1) / (2x2) = 1/4

4 0
3 years ago
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At the fair,Kate found a strange machine with a sign on it labeled, enter a number. When she pushed the number 15, the machine d
Ivan

apparently subtracting 6

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6 0
3 years ago
How many 2-letter combinations can be made from the letters A, B, C, and D?
yulyashka [42]

Answer:

12

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5 0
2 years ago
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What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
2 years ago
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