The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.
Answer:
1. 2^9 = 512
2. 2^3 = 8
3. 7^3 = 343
4. 6^3 = 216
5. 3^6 = 729
Step-by-step explanation:
To start we have to express the number as a multiplication of prime numbers, from there we can take the expression as a power
1.
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 512
2^9 = 512
2.
2 x 2 x 2 = 8
2^3 = 8
3.
7 x 7 x 7 = 343
7^3 = 343
4.
6 x 6 x 6 = 216
6^3 = 216
5.
3 x 3 x 3 x 3 x 3 x 3 = 729
3^6 = 729
Answer:
About 5,000 kilograms
Step-by-step explanation:
Look on the x-axis for 18 years. Then go up to where the plotted line is on 18 years to find the y-axis or the mass.
You can set up a systems of equations to solve this problem.
The equation y = 2x-3 represents the father's age where y = The father's age and x = The son's age.
The equation 30=y-x represents the difference between the two ages.
In order to be able to solve a system, the two equations can be in the same form. (They don't need to be it's just easier for me to have them in the same form) One is in standard form (ax+by= c) and the other one is in slope intercept form (y=mx+b where m is the slope and b is the y- intercept).
Lets put the equation y=2x-3 into standard form.
y=2x-3
+3 +3
y+3=2x
-y -y
3=2x-y
We have the two equations 30=y-x and 3=2x-y
Now to solve the system.
30=y-x
3=2x-y or 3=-y+2x
30=y-x
3=-y+2x The -y and y cancel each other out since they are the same term but are the inverse of each other one is neg one is pos.
Your left with
30=-x Now you just combine the two equations. 30+3 and 2x-x
3=2x
33=x The son's age is 33. To Find the Fathers age we would just plug 33 for x into one of the equations to find the Fathers age.
SON'S AGE IS 33
. This admits the two fundamental solutions
is the Wronskian of the fundamental solutions. We have
