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Lady_Fox [76]
3 years ago
6

30 20 Y Find x Can someone please help me

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos30° = \frac{\sqrt{3} }{2} , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{x}{20} = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 20\sqrt{3} ( divide both sides by 2 )

x = 10\sqrt{3} → B

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Is -27 divided by (-3) positive or negative & how
zloy xaker [14]

Answer:

9

Step-by-step explanation:

-27/-3

27/3 is 9

each of them have a negative so it stays positive

9

7 0
3 years ago
Read 2 more answers
Rearrange the formula to make x the subject:<br> A = 1/2xy
Maslowich

Answer:

x = \frac{2A}{y}

Step-by-step explanation:

Given

A = \frac{1}{2} xy

Multiply both sides by 2 to clear the fraction

2A = xy ( divide both sides by y )

\frac{2A}{y} = x

3 0
3 years ago
What’s the answer to number 1 ? Show how you solved please !!!!
Elodia [21]
Dan had 52
shown work: 29 x 2=58 58-6=52
5 0
3 years ago
23 please thanks soooooo much
Kisachek [45]
I can't see the whole diagram.. Can u fix the picture
6 0
4 years ago
Which line contains the point (1,-3)
Rzqust [24]
There are infinitely many lines that have the point (1,-3).

A line can be expressed as:

y=mx+b, where m=slope and b=y-intercept..

Our only restriction is that it passes through (1,-3) so

-3=1m+b

So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)

So we could also say b=-3-m then our infinite lines are:

y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are

y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2


4 0
4 years ago
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