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4 years ago

Find the equation of the line through the points (−2,7) and (0,5).

Mathematics

1 answer:

DerKrebs [107]4 years ago

6 0

Answer:

y=-x+5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-7)/(0-(-2))

m=-2/(0+2)

m=-2/2

m=-1

y-y1=m(x-x1)

y-7=-1(x-(-2))

y-7=-(x+2)

y=-x-2+7

y=-x+5

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Andreas plays soccer video game he earns three stars for every goal he scores and loses 3/4 stars every time he misses the goal

lakkis [162]

Answer: 12 stars

Step-by-step explanation:

First find out the number of stars he gained by scoring goals:

= Number of goals scored * Stars if goal is scored

= 5 * 3

= 15 stars

Then find out the number of stars he is to lose by missing the goal:

= No. of goals missed * stars if goal missed

= 4 * 3/4 stars

= 3 stars

The total number of stars he has are:

= Stars gained - Stars lost

= 15 - 3

= 12 stars

3 0

3 years ago

Find the x and y intercept of the equation: 8x+4y=24

myrzilka [38]

8x=24 which is 3 so x = 3

4y=24 which is 6 so y = 6
(3,0) for x and (0,6) for y

5 0

3 years ago

Given f(x)=3x+12, find f(f^-1(0))

mamaluj [8]

Answer:

Step-by-step explanation:

METHOD 1.

We know:

$f\bigg(f^{-1}(x)\bigg)=x$

Therefore

$f\bigg(f^{-1}(0)\bigg)=0$

METHOD 2.

$\text{Find}\ f^{-1}(x)$

$f(x)=3x+12\to y=3x+12$

exchange x to y and vice versa:

$x=3y+12$

solve for y:

$3y+12=x$ subtract 12 from both sides

$3y=x-12$ divide both sides by 3

$y=\dfrac{x-12}{3}\to f^{-1}(x)=\dfrac{x-12}{3}$

$f\bigg(f^{-1}(x)\bigg)\to$ replace x in f(x) with the expression $\dfrac{x-12}{3}$

$f\bigg(f^{-1}(x)\bigg)=3\cdot\dfrac{x-12}{3}+12=x-12+12=x$

$f\bigg(f^{-1}(0)\bigg)\to$ put x = 0 to $f\bigg(f^{-1}(x)\bigg)=x$

$f\bigg(f^{-1}(0)\bigg)=0$

METHOD 3.

$\text{Find}\ f^{-1}(x)$

$f^{-1}(x)=\dfrac{x-12}{3}$

Calculate the value of f ⁻¹(x) for x = 0:

$f^{-1}(0)=\dfrac{0-12}{3}=\dfrac{-12}{3}=-4$

Calculate the value of f(x) for x = -4:

$f(4)=3(-4)+12=-12+12=0$

6 0

3 years ago

Worth 10 points It’s a picture so it’s clear

Klio2033 [76]

Diameter because it’s the diameter

5 0

3 years ago

Read 2 more answers

A bike tire just ran over a nail, and it is losing pressure at a rate of 5% every minute. The tire pressure is currently 1,300 k

AlexFokin [52]

Answer:

1,114.6 kPa

Step-by-step explanation:

P(t) = 1300 (0.95)^t

P(3) = 1300 (0.95)^3

P(3) = 1114.6

5 0

4 years ago