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Serjik [45]
4 years ago
13

type the equation that shows the relationship between the variables in this chart: x: 1,2,3,4,5 and y: 7,14,21,28,35

Mathematics
1 answer:
Nonamiya [84]4 years ago
4 0
The equation that relates the x and y values in the chart above is: y = 7x. It can be observed that each value of x when multiplied with a factor of 7 gives the corresponding y value. For example, for x equals 1, y is equal to 7 times 1 which gives a value of 7. For x equals 5, the y value is equal to 7 times 5 which gives the number 35.
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Troyanec [42]

Answer:

The square root of 2, or the (1/2)th power of 2, written in mathematics as √2 or 21⁄2

6 0
4 years ago
A comic-strip writer churns out different numbers of comic strips each day. The writer logged the number of comic strips he wrot
VLD [36.1K]

Answer:

Step-by-step explanation:

Given that a comic-strip writer churns out different numbers of comic strips each day. The writer logged the number of comic strips he wrote each day for 16 days and sorted the data in ascending order to create this data set.

1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8

Mean = 3.77 and median =3.5

When mean > median, hence positively skewed.

skewness = 0.74

If 5 and 7 are added the data set in ascending order is

1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5,5. 6, 7,8

Mean = 3.7778 and median = 3.5

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3 0
3 years ago
Anu bought 15 stickers for 225 each and Arjun bought 25 stickers for 215 each. Who paid more? Give a reason for your answer.​
ahrayia [7]

Answer: Arjun paid more than Anu of about $2000.

Total cost

unit amount × per unit cost

For Anu total cost:

⇒ 15 × $225

⇒ $3375

For Arjun total cost:

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Conclusion: Arjun paid more.

4 0
2 years ago
What the answer to 30-32
kifflom [539]

30. C & D

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3 0
3 years ago
Factor the following expression completely:<br> 16x^5 - x^3
myrzilka [38]

Assignment: \bold{Factor \ 16x^5 - x^3}

<><><><><>

Answer: \boxed{\bold{x^3\left(4x+1\right)\left(4x-1\right)}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Factor out common term \bold{x^{3}}

\bold{x^3\left(16x^2-1\right)}

[ Step Two ] Factor \bold{16x^2-1}

\left(4x\right)^2-1^2

[ Step Three ] Rewrite equation

\bold{x^3\left(4x+1\right)\left(4x-1\right)}

<><><><><><><>

\bold{\rightarrow Rhythm \ Bot \leftarrow}

3 0
3 years ago
Read 2 more answers
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