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3 years ago

14

The cost of 6one by two metere

1 answer:

Alik [6]3 years ago

5 0

Answer:

Rs 17 3/4

Step-by-step explanation:

Cost of 6 1/2 m = 115 3/8

Cost of 1 m = x

x = 115 3/8 ÷ 6 1/2
x = (115*8 +3)/8 ÷ 13/2
x = 923/8 × 2/13
x = 923/(4*13)
x = 923/52
x = 17 39/52
x = 17 3/4

Cost of 1 meter is Rs 17 3/4

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Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

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Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

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This is the average of the 3rd and the 4th element

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<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

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$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

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<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

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$IQR(1.5) = 12 \times 1.5$

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The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

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