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3 years ago

A crayon company sells a pack of wax crayons for $5. there are 10 crayons in each pack. what is the unit price of the crayons?

Mathematics

2 answers:

creativ13 [48]3 years ago

7 0

Answer:

Unit price of the crayons is $0.5 or 50 cents.

Step-by-step explanation:

A crayon company sells a pack of wax crayon for $5.

Since each pack contains number of crayons = 10

Then we have to find the unit price of the crayons.

We apply unitary method to solve this question.

∵ 10 crayons cost = $5

∴ 1 crayon will cost = $\frac{5}{10}$

= $0.5

Therefore, unit price of the crayons will be $0.5 or 50 cents.

Nutka1998 [239]3 years ago

4 0

The unit price of the crayons is 50 cents

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Find the zeros of the function. Write the smaller solution first, and the larger solution second. f(x)=(x+8)^2−1

BartSMP [9]

Answer:

zeroes: x = -9 and x = -7

Step-by-step explanation:

f(x)=(x+8)^2−1

A "zero" refers to when the y-value on the graph is zero.

0 = (x+8)^2 - 1

1 = (x+8)^2

+ or - 1 = x+8

so break them apart into two equations

x+8 = 1 OR x+8 = -1

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You can plug both back in to check that the equation works!

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4 years ago

A store manager begins each shift with the same total amount of money. She keeps $200 in a safe and distributes the rest equally

lina2011 [118]

Answer:

The answer would be 5

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3 years ago

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Given P = x^0.3 y^0.7 is the chicken lay eggs production function, where P is the number of eggs lay, x is the number of workers

lora16 [44]

Answer:

Part A)

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}$

Part B)

The daily operating cost decreases by about $143 per extra worker.

Step-by-step explanation:

We are given the equation:

$\displaystyle P=x^{\frac{3}{10}}y^{\frac{7}{10}}$

Where P is the number of eggs laid, x is the number of workers, and y is the daily operating budget (assuming in US dollars $).

We want to find dy/dx.

So, let’s find our equation in terms of x. We can raise both sides to 10/7. Hence:

$\displaystyle P^\frac{10}{7}=\Big(x^\frac{3}{10}y^\frac{7}{10}\Big)^\frac{10}{7}$

Simplify:

$\displaystyle P^\frac{10}{7}=x^\frac{3}{7}y$

Divide both sides by the x term to acquire:

$\displaystyle y=P^\frac{10}{7}x^{-\frac{3}{7}}$

Take the derivative of both sides with respect to x:

$\displaystyle \frac{dy}{dx}=\frac{d}{dx}\Big[P^\frac{10}{7}x^{-\frac{3}{7}}\Big]$

Apply power rule. Note that P is simply a constant. Hence:

$\displaystyle \frac{dy}{dx}=P^\frac{10}{7}(-\frac{3}{7})(x^{-\frac{10}{7}})$

Simplify. Hence, our derivative is:

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}$

Part B)

We want to evaluate the derivative when x is 30 and when y is $10,000.

First, we will need to find P. Our original equations tells us that:

$P=x^{0.3}y^{0.7}$

Hence, at x = 30 and at y = 10,000, P is:

$P=(30)^{0.3}(10000)^{0.7}$

Therefore, for our derivative, we will have:

$\displaystyle \frac{dy}{dx}=-\frac{3}{7}\Big(30^{0.3}(10000^{0.7})\Big)^\frac{10}{7}\Big(30^{-\frac{10}{7}}\Big)$

Use a calculator. So:

$\displaystyle \frac{dy}{dx}=-\frac{1000}{7}=-142.857142...\approx-143$

Our derivative is given by dy/dx. So, it represents the change in the daily operating cost over the change in the number of workers.

So, when there are 30 workers with a daily operating cost of $10,000 producing a total of about 1750 eggs, the daily operating cost decreases by about $143 per extra worker.

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Law Incorporation [45]

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Reil [10]

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