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Semmy [17]
4 years ago
6

Wren has a 30% chance of being selected as the president of the school sports club and a 80% chance of being elected editor of t

he school magazine.
What is the probability that Wren will be selected as the president of the sports club and will also be elected editor of the school magazine?
A) 11%
B) 15%
C) 24%
D) 50%
Mathematics
2 answers:
anyanavicka [17]4 years ago
4 0

Answer with Step-by-step explanation:

Wren has a 30% chance of being selected as the president of the school sports club and a 80% chance of being elected editor of the school magazine.

What is the probability that Wren will be selected as the president of the sports club and will also be elected editor of the school magazine?

A: Wren will be elected president of the school

P(A)=0.3     (30%)

B: Wren will be elected editor of school magazine

P(B)=0.8   (80%)

Both the events are independent hence,

P(A∩B)=P( Wren will be selected as the president of the sports club and will also be elected editor of the school magazine)

             = P(A)×P(B)

           = 0.3×0.8

          =0.24

          = 24%

Hence, the probability that Wren will be selected as the president of the sports club and will also be elected editor of the school magazine

C) 24%

SashulF [63]4 years ago
3 0
Multiply the two probabilities together to get the answer. 3/10 ×8/10 = 24/100 or 24 %
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r^2=32

r=sqrt(32)

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r=4*sqrt(2)

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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125
Savatey [412]

we have that

300 + 150 + 75 +...

Let

a1=300\\ a2=150\\ a3=75

we know that

\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50

\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50

so

a(n+1)=an*0.50

Is a geometric sequence

Find the value of a4

a(4)=a3*0.50

a(4)=75*0.50

a(4)=37.5

Find the value of a5

a(5)=a4*0.50

a(5)=37.5*0.50

a(5)=18.75

Find S5

S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25

therefore

the answer is

581.25

Alternative Method

Applying the formula

S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25

therefore

the answer is

581.25

6 0
3 years ago
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