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suter [353]
3 years ago
8

You earned the following scores on four english tests: 96, 88, 74, and 76. The greatest score you can earn on a test is 100. Is

it possible for you to have an average score of 91 or higher after the fifth test?
Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

No

Step-by-step explanation:

96+88+74+76=334/4=83.5

96+88+74+76+100=434/5=86.8

The average can't be higher than a 91%

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Combine any like terms in the expression. If there are no like terms, rewrite the expression.
Llana [10]
If the 3’s were exponents then... i got 50r3

how i solved:

39r3 + 11r3 + 45s3 - 5s3 - 40s3

50r3 + 40s3 - 40s3

50r3 + 0

= 50r3
4 0
3 years ago
You bought a large container of fruit punch. The label on the container says there are 128 FL Oz of fruit punch in the container
Lina20 [59]
Well, one cup is 8 fluid ounces.  So 128/8 = 16 cups.
8 0
3 years ago
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Five less than twice a number is seven
mart [117]

Answer:

2x - 5 = 7

2x -5 + 5 = 7 + 5

2x = 12

2/2x = 12/2

x = 6

Step-by-step explanation:

3 0
3 years ago
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How do you this question (pre-cal)
Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into \csc^2( B )

One way we can do that is through the following steps:

\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0
3 years ago
Michael breeds chickens and ducks.
hodyreva [135]
Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.
4 0
3 years ago
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