Answer:
The park is <u>31 inches</u> wide in the drawing.
Step-by-step explanation:
Given:
Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.
The actual width of a neighborhood park is 62 yards.
Now, to find the width of park in drawing.
Let the width of park in drawing be 
The scale drawing of the city is 1 inch : 2 yards.
So, 1 inch is equivalent to 2 yards.
Thus, 
is equivalent to 62 yards.
Now, to get the width of park in drawing by using cross multiplication method:
By cross multiplying we get:
Dividing both sides by 2 we get:
Therefore, the park is 31 inches wide in the drawing.
The cost to equip all the stations in the chemistry lab is calculated as: $393.75.
<h3>How to Calculate Total Cost?</h3>
In this scenario, we are given the following:
Total number of stations = 21 stations
Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet
Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet
Cost of 1 rubber tubing = $6.25 per yard
Convert 5 feet to yard:
1 yard = 3 feet
x yard = 5 feet
x = (5 × 1)/3
x = 5/3 feet.
So, the cost of 1 rubber tubing = $6.25 per 5/3
Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5
Cost of total length of tubbing needed = $393.75
Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.
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Answer: After 1 year: $5,610
After 2 years: $5,722.20
Step-by-step explanation: Use the formula for periodic compounding interest, which is
A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.
Here, P = 5,500, r = 0.02 (that's 2% as a decimal), n = 1,
t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)
Plug the known values in to solve...
For 1 year...
A = 5,500(1 + 0.02/1)^(1*1)
A = 5,500(1.02)^1
A = 5,610
For 2 years...
A = 5,500(1 + 0.02/1)^(1*2)
A = 5,500(1.02)²
A = 5,722.20
Answer:
sq. units.
Step-by-step explanation:
The given function is
We need to find the area between x-axis and the given function from x=2 to x=5.
Left Riemann sum formula of area:
For given question,
Now,
Therefore, the required area is sq. units.
Yes, it matters, if it is recurring or simply just irrational <span />
