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3 years ago

A book store contains 75,972 books, divided in three sections: Science, Business, and Math.

1 answer:

3 0

The answer is 12,662 books in the math section.

Since the science section represents 1/3 of the total books, divide 75,972 by 3.

75,972 ÷ 3 = 25,324 books in the science section.

Now, subtract 25,324 science books from the total number of books.

75,972 - 25,324 = 50,648 remaining books.

Divide the remaining books by 4 and then multiply by 3.

50,648 ÷ 4 = 12,662 • 3 = 37,986 business books.

Add the science books and business books together.

25,324 + 37,986 = 63,310 science and business books.

Subtract 63,310 from 75,972.

75,972 - 63,310 = 12,662 books in the math section.

Hope I helped!

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Trey’s desk is 3 feet wide. How many inches wide is the desk? A:3 inches B:24 inches C:36 inches or D: 48 inches

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Answer:

Step-by-step explanation:

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3 years ago

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Given sin theta = 1/3 and 0 theta pi/2 find tan 2 theta

Kazeer [188]

Answer:

$\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}$

Step-by-step explanation:

Given: $\sin\theta = \dfrac{1}{3}$

$0\leq \theta \leq \dfrac{\pi}{2}$

Theta lie in first quadrant.

Multiply both sides by 2

$0\leq 2\theta \leq \pi$

2theta lie in I and II quadrant.

$\tan2\theta$ is positive in I and negative in II quadrant.

$\sin\theta=\dfrac{1}{3}$

$\cos\theta=\dfrac{2\sqrt{2}}{3}$

$\sin2\theta=2\sin\theta\cos\theta$

$\sin2\theta=2\cdot \dfrac{1}{3}\cdot \dfrac{2\sqrt{2}}{3}=\dfrac{4\sqrt{2}}{9}$

$\cos2\theta=\pm \sqrt{1-\sin^22\theta}=\pm\dfrac{7}{9}$

$\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}$

$\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}$

Hence, The value of $\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}$

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3 years ago

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WHO WANTS BRANLIEST?!?!?!?!?!?!?!?

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Answer:

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Step-by-step explanation:

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3 years ago

Which triangle drfined by the given points on the coordinate plane is similar to the triangle illustrated?

Harrizon [31]

Answer:D.) (-1, 1), (-1, 5), (-7, 1)

Step-by-step explanation:The length of the horizontal segment of the triangle graphed is 3. The length of the vertical segment of the triangle graphed is 2. Using the Pythagorean theorem, this makes the length of the missing side

2²+3²=c²

4+9 = c²

13=c²

√13 = c

This makes our side lengths 2, 3, and √13.

For choice A our vertices are (-1, 1), (-1, 4), (-6, 1).

This makes the length of the horizontal segment 5 and the length of the vertical segment 3. This makes the missing side length

5²+3²=c²

25+9=c²

34=c²

√34 = c

This is not proportional to the triangle drawn, so it is not similar.

The vertices of the triangle in option B are (-1, 1), (-1, 5), and (-6, 1). This makes the horizontal segment 5 units long and the vertical segment 4 units long. This makes the missing side length

4²+5²=c²

16+25=c²

41=c²

√41=c

These are not proportional to the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice C are (-1, 1), (-1, 4) and (-7, 1). This makes the length of the horizontal segment 6 and the length of the vertical segment 3. This makes the missing side length

3²+6²=c²

9+36=c²

45=c²

√45=c

3√5=c

These sides are not proportional to the sides of the triangle drawn, so the triangles are not similar.

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These sides are all twice as long as the sides of the triangle drawn; this means the triangles are similar.

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3 years ago

Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among

Olegator [25]

Answer:

a) X[bar]₁= 1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= $\frac{1}{n_1-1}$ [∑X₁² - (( ∑X₁)²/n₁)]= $\frac{1}{14} + [52829538 - (\frac{27588^{2} }{15})$ = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

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3 years ago