3 years ago

Please help i will give brainliest pls don’t answer if you don’t know

Mathematics

1 answer:

Kamila [148]3 years ago

4 0

Answer:

-4x-5

Step-by-step explanation:

3+x-(x+2)-4x

3+x-x-2-4x

-4x-5

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3 years ago

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3 years ago

What are the possible values of x in x2 + 3x + 3 = 0?

e-lub [12.9K]

To solve a quadratic equation like $ax^2+bx+c=0$ , you can use the quadratic formula

$x_{1,2} = \cfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, $a = 1, b = c = 3$ , so the formula becomes

$x_{1,2} = \cfrac{-3\pm\sqrt{(-3)^2-4\cdot 1\cdot 3}}{2\cdot 1}$

We can simplify the expression:

$x_{1,2} = \cfrac{-3\pm\sqrt{9-12}}{2} = \cfrac{-3\pm\sqrt{-3}}{2}$

Since -3 is negative, its square root is computed as

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So, the solutions are

$x = \cfrac{-3+i\sqrt{3}}{2} \text{ or } x = \cfrac{-3-i\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers