Hello,
x,y,z∈ IN





==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
A. the outlier is 37
B. the mean with the outlier is 20
C. the mean without the outlier is 17.5
1-2.25x8=(1-1.5x^4)(1+1.5x^4)
=(1-√1.5 x²)(1+√1.5 x²)(1+1.5 x^4)
=(1-√√1.5 x)(1+√√1.5 x)(1+√1.5 x²) (1+√1.5 x^4)
hope I'm right but either 2 or 4 i can kinda go either way
Answer: 125 ft.
Step-by-step explanation:
Assuming the perimeter of the park is 400 ft, the equation can be represented as
2l + 2w = 400
Since we know that the width is 50 ft shorter than the length, using algebra, you replace the variable w, with
2l + 2(l-50) = 400
Then, solve for variable l, or length
2l +2l - 100 = 400
4l = 500
l = 125
Now, plug in l and solve for w
2(125) + 2w = 400
250 + 2w = 400
2w = 150
w = 75
2(125) + 2(75) = 400
250+150 = 400
400=400
l = 125, w = 75
So the length is 125 ft