Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Answer:
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°
Step-by-step explanation:
`From the given picture,
Angle SOP and angle SOR are the linear pairs.
Therefore, sum of these angles will be equal to to 180°.
m∠SOP + m∠SOR = 180° -----(1)
Since, m∠SOP = (7x - 2)° and m∠SOR = (5x + 14)°
[There is a misprint in this question. There should be x in place of y in the measures of the angles]
By substituting these values in the equation (1),
(7x - 2) + (5x + 14) = 180
12x + 12 = 180
12x = 180 - 12
12x = 168
x = 
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°
One pound is equivalent to 16 ounces.
Thus, multiply 14 pounds with 16 to get the number of ounces.
14 pounds equals 224 ounces. Let me know if you need any clarifications, thanks!
~ Padoru
