3 years ago

Select the fraction that would be included in an equivalence chain for 1/4.

1 answer:

4 0

Take it bye 1)2 so it gives u ur anser so there u are

You might be interested in

timama [110]

Answer:

Step-by-step explanation:

3 0

3 years ago

strojnjashka [21]

$\begin{cases}c_0=5\\c_n={c_{n-1}}^2&\text{for }n\ge1\end{cases}$

For $n=1$ , we have by this definition $c_1={c_0}^2=5^2$ which is equal to $5^{2^n}$ for $n=1$ .

Assume $c_n=5^{2^n}$ for some $n=k$ . We want to use this to show that this implies $c_{k+1}=5^{2^{k+1}}$ . By the recursive definition,

$c_{k+1}={c_k}^2=(5^{2^k})^2=5^{2^{k+1}}$

and we're done.

$\begin{cases}b_0=1\\b_n=2b_{n-1}+1&\text{for }n\ge1\end{cases}$

For $n=0$ , we have $b_0=1$ , and $2^{n+1}-1=1$ .

Assume $b_n=2^{n+1}-1$ for some $n=k$ . Then for $n=k+1$ , we have

$b_{k+1}=2b_k+1=2\left(2^{k+1}-1\right)+1=2^{k+2}-1$

and we're done.

8 0

3 years ago

guapka [62]

You would pay 14 dollars for 7 Powerades

5 0

3 years ago

xxTIMURxx [149]

Answer:

42,5000

Step-by-step explanation:

8 0

2 years ago

AleksandrR [38]

Step-by-step explanation:

12x + 3(x - 4) + 2x

17x-12

HOPE IT HELPS U

8 0

3 years ago