2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
She gave away 8 apples because 13 minus 5 is 8
Answer:
{- 3, - 2, 0, 2 }
Step-by-step explanation:
The range is the y- coordinates of the points
(- 4, - 3 ) , (- 1, - 2 ) , (- 2, 0 ) , (0, 2 )
The y- coordinates are - 3, - 2, 0, 2
Then the range is { - 3, - 2, 0, 2 }
Answer:
<h2>100</h2>
Step-by-step explanation:
BIDMAS
do the bracket first
50+20=70
70+30=100
