Answer:
30 Chairs
Step-by-step explanation:
I will solve this problem using algebra and try to explain in detail.
We can form two equations with the information given to us.
Firstly, 5 times a length of chairs (I will call this unknown length of chairs x), plus 5 left over chairs, equals the total number of chairs (I will call the total number of chairs y).
5x + 5 = y
Secondly, 3 times a length of chairs (I will call this unknown length of chairs x), plus 15 left over chairs, equals the total number of chairs (I will call the total number of chairs y).
3x + 15 = y
Since both equations are equal to y, they are equal to each other
5x + 5 = 3x + 15
Take 5 away from both sides of the equals, and take away 3x from both sides of the equals
5x - 3x = 15 - 5
2x = 10
Divide both sides by 2
x = 5 chairs
Put this back into either the first equation or the second to solve for y
3 (5) + 15 = y
15 + 15 = y
y = 30 chairs
<u>Answer:</u>
-4
<u>Step-by-step explanation:</u>
We are given the following expression which we are to solve:
![( - 4 ) 5 - ( - 6 ) ( - 4 ) + 4 0](https://tex.z-dn.net/?f=%20%28%20-%204%20%29%205%20-%20%28%20-%206%20%29%20%28%20-%204%20%29%20%2B%204%200%20)
Since this expression includes brackets as well has plus and minus signs, so we will follow the standard order of operations to solve this expression.
Solving the brackets first to get:
![( - 2 0 ) - ( 2 4 ) + 4 0](https://tex.z-dn.net/?f=%20%28%20-%202%200%20%29%20-%20%28%202%204%20%29%20%2B%204%200%20)
Now adding all the terms up to get:
-4
Jenna has 35 Quarters and 15 Dimes.
It’s literally 1/4 because 4/4 is one and you have 1/4 left over
Answer:
13.98 degrees
Step-by-step explanation:
Let the airplane be at point A, the airport at point B and the point of overshoot, point C.
If the plane is on path AC and the pilot wants to adjust to the path AB, the angle by which the pilot will adjust the airplane heading is the angle between AB and AC which is A.
Using Cosine Rule
![Cos A=\dfrac{b^2+c^2-a^2}{2bc} \\Cos A=\dfrac{65^2+60^2-16^2}{2(65)(60)} \\Cos A=0.9704\\A=arcCos (0.9704)\\\angle A=13.98^\circ](https://tex.z-dn.net/?f=Cos%20A%3D%5Cdfrac%7Bb%5E2%2Bc%5E2-a%5E2%7D%7B2bc%7D%20%5C%5CCos%20A%3D%5Cdfrac%7B65%5E2%2B60%5E2-16%5E2%7D%7B2%2865%29%2860%29%7D%20%5C%5CCos%20A%3D0.9704%5C%5CA%3DarcCos%20%280.9704%29%5C%5C%5Cangle%20A%3D13.98%5E%5Ccirc)
The pilot should adjust the plane's heading by 13.98 degrees.