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kondaur [170]
2 years ago
5

A restaurant has 60 tables. The graph shows the average number of tables occupied during each day of the week. During which day

does the restaurant have the least empty tables?
sunday
Monday
wednsday
saturday

Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

Answer: Saturday

Step-by-step explanation:

Saturday is at the highest point meaning it has less empty tables

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Write a standard is the number seventy-two and seventeen thousandths then round the nearest hundredths
Natali5045456 [20]

Answer:

72.017

Step-by-step explanation:

Rounded to the nearest hundredths: 72.02

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Which store has the better buy? Pet Smart sells 20 pounds of pet food for $13.99 or Chewy sells 50 pounds of pet food for $37.99
zimovet [89]

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pet smart sell

Step-by-step explanation:

because it is cheaper than other sell

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3 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
Please help with this paper!! asap please
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1 is L
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Look back at your notes if you have any.


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