Answer:
y + 6 = -
(x + 10)
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 4x ← is in slope- intercept form
with slope m = 4
given a line with slope m then the slope of a line perpendicular to it is
= -
= - ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
here m = -
and (a, b ) = (- 10, - 6 ) , then
y - (- 6) = -
(x - (- 10) ) , that is
y + 6 = -
(x + 10)
Look online and find the answers to the workbook that's what I did and I never failed workbook things
The first step before graphing these is to ensure they are both in y=mx+b (slope-intercept) format.
Only the first one (y-2x=0) is not.
To convert this to slope-intercept form, just add 2x to both sides so y is isolated!
This leaves us with y=2x+0, which is in slope-intercept form.
When graphing these, you must identify the slope and the y-intercept.
In y=mx+b form, the m is slope and b is y-intercept.
In y=2x+0, the slope is 2 and the y-intercept is 0.
This means there is a slope of positive 2 and the y-intercept is (0, 0).
The y-intercept is the y-value where ever x=0.
In y=6x-10, the slope is 6 and the y-intercept is -10.
This means there is a slope of positive 6 and the y-intercept is (0, -10).
Hope this helps! :)