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MariettaO [177]
3 years ago
12

A line passes through the point (4, –3) and has slope m = 1. Find the equation in point–slope form.

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

The expected answer is ...

  y +3 = x -4

Step-by-step explanation:

The line with slope m through point (h, k) can be written in point-slope form as ...

  y -k = m(x -h)

For (h, k) = (4, -3) and m=1, the filled-in form is ...

  y +3 = x -4

___

It happens that the same line can be described by ...

  y +4 = x -3 . . . . . matches the second choice

because that line also goes through the point (3, -4).

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A≈1256.64 m² thats the answer
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3 years ago
AB=6CM AC= 12cm <br> calculate the length of CD
Brrunno [24]

AB=6cm AC=12cm

AC² = AB + BC²

12² = 6² + CB²

CB² = 12² - 6²

CB² = 144 - 36

CB² = 108

CB = √ 108 cm.

sin 55° = CB / CD

0.81915 = √108 / CD

CD = 10.392 / 0.81915

CD = 12.686 cm

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3 years ago
Read 2 more answers
Suppose X has a continuous uniform distribution over the interval [1.3, 6.2]. Round your answers to 3 decimal places.
goldenfox [79]

Answer:

(a) 3.75

(b) 2.00083

(c) 0.4898

Step-by-step explanation:

It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].

(a)

Compute the mean of X as follows:

\mu_{X}=\frac{a+b}{2}=\frac{1.3+6.2}{2}=3.75

(b)

Compute the variance of X as follows:

\sigm^{2}_{X}=\frac{(b-a)^{2}}{12}=\frac{(6.2-1.3)^{2}}{12}=2.00083

(c)

Compute the value of P(X < 3.7) as follows:

P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898

Thus, the value of P(X < 3.7)  is 0.4898.

5 0
2 years ago
Does anyone know what this is?
KIM [24]

Answer:

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Step-by-step explanation:

90÷2 = 45

8 0
3 years ago
Read 2 more answers
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

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\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
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