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Phantasy [73]
3 years ago
12

What is the maximum number of squares that could be formed using four of the dots in the unit grid as vertices.

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
22 is the maximum number of squares that can be formed
lina2011 [118]3 years ago
6 0
5 yup tup yup tupyjjrjrjr
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Convert 29,000 mm2 into cm2
torisob [31]

Answer:

290 cm2

Step-by-step explanation:

7 0
3 years ago
Which climate zone generally receives the least amount of the
Delicious77 [7]

Answer:

d) subpolar zone

3 0
3 years ago
PLEASE HELP
Mila [183]

Answer:

The value of b = -2.7

Step-by-step explanation:

Given

As  the equation is given by

-5=b-2.3

To determine

Solve the equation for b

Given the equation

-5=b-2.3

switch the sides

b-2.3=-5

Add 2.3 to both sides

b-2.3+2.3=-5+2.3

Simplify

b=-2.7

Therefore, the value of b = -2.7

4 0
3 years ago
Read 2 more answers
Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?
Feliz [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see

\bf h(x)=-x+5\implies h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\stackrel{D}{+5}

a shift down by 3 units, means a vertical shift downwards, so D needs to drop by 3 units.

\bf h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\boxed{\stackrel{D}{+5-3}}\implies h(x)=-1(1x+0)+2
\\\\\\
h(x)=-x+2
4 0
3 years ago
Give a combinatorial proof that the cardinality of the power set of a finite set A is 2^|A|
juin [17]

There are \dbinom{|A|}k ways of building a subset of k elements from A, so the total number of subsets you can build is

\displaystyle\sum_{k=0}^{|A|}\binom{|A|}k

Recalling the binomial theorem, the above sum is equal to

\displaystyle\sum_{k=0}^{|A|}\binom{|A|}k1^k1^{|A|-k}=(1+1)^{|A|}=2^{|A|}

as required.

3 0
4 years ago
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