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3 years ago

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Mathematics

1 answer:

labwork [276]3 years ago

8 0

The correct answer would be C

Hope this helped

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Please Help! What is the distance between points (2, 8) and (7, 5)? Round to the nearest tenth of a unit.

zavuch27 [327]

Distance formula is like pythagoren ahtoerem
D= $\sqrt{(7-2)^{2}+(5-8)^{2}}$
the distance between oints (x1,y1) and (x2,y2) is
D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$
(2,8) and (7,5)
D= $\sqrt{(7-2)^{2}+(5-8)^{2}}$
D= $\sqrt{(5)^{2}+(-3)^{2}}$
D= $\sqrt{25+9}$
D= $\sqrt{34}$
apxos
D=5.8309....

round
D=5.8 units

6 0

3 years ago

Read 2 more answers

What is the simplified form of each expression?

eimsori [14]

IM pretty sure the answer is
1.A
2.C
3.A
4.D
5.B
:)

3 0

3 years ago

Read 2 more answers

Find the value of x.<br> 50

Mariana [72]

Answer:

x = 18 degrees

Step-by-step explanation:

50 - 32 = 18

7 0

2 years ago

Read 2 more answers

Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.

sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of Homogeneity.

The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.

C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0

3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago