Answer: P=$7,1333.33
Step-by-step explanation:
Equation: P=A/(1+rt)
z=3/8
Step-by-step explanation:
Step by step summary
We have to remember some of these basic indices’ corollary
- (1/a)ⁿ = (a)⁻ⁿ
- (a²)ⁿ = (a)²ⁿ
- (a)ᵇ.(a)ⁿ = (a)ᵇ⁺ⁿ
Using these corollaries we would proceed with the problem
(1/4)^(3z-1)= (4)^(1-3z) using 1 theorem
Similarly
(16)^ (z+2)= (4)^(2(z+2)) using 2nd theorem
(64)^ (z-2)=(4)^ (3(z-2)) using 2nd theorem
Solving above 2 equations we get
(4)^(2z+4). (4)^(3z-6)
(4)^(2z+4+3z-6) using 3rd theorem
(4)^(5z-2)
Thus, we get the equation
(4)^(1-3z) = (4)^(5z-2)
Since the bases are the same we could equate the powers
1-3z=5z-2
8z=3
Z=3/8
Answer:
29
Step-by-step explanation:
9514 1404 393
Answer:
- B → X
- C → Y
- D → Z
- 180° rotation about the origin
Step-by-step explanation:
In general, if PQ is rotated to P'Q', the center of rotation (O) will be the point of intersection of the perpendicular bisectors of PP' and QQ'. The angle of rotation will be the angle POP', or QOQ'.
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The correspondence between preimage vertices ABCD and image vertices can be found by naming the vertices in the same order (clockwise) from one whose correspondence you know.
Here, the correspondence between A and W is given. Vertices clockwise from W are WXYZ, so those are the image points corresponding to ABCD.
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We note that the midpoints of AW and BX are coincident at the origin. That is, the perpendicular bisectors of these segments are coincident at the origin, so the origin (point O) is the center of rotation. The rotation angle is AOW, an angle that measures 180°.
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The image point coordinates are the opposites of the preimage point coordinates.
A(2, 2) ⇒ W(-2, -2)
B(2, 5) ⇒ X(-2, -5)
C(5, 5) ⇒ Y(-5, -5)
D(5, 2) ⇒ Z(-5, -2)
This is another indication that the rotation is 180° about the origin, since that rotation results in the mapping ...
(x, y) ⇒ (-x, -y) . . . . . rotation 180° about the origin
Answer:
420 (lol)
Step-by-step explanation:
