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Natali [406]
3 years ago
13

Seven added to double a number

Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0
<h3>Correct Question :</h3>

Express in arithmetic :

Seven added to double a number.

<h3>Solution :</h3>

Let the unknown be x.

Then, double of the number = 2x.

Atq,

2x+7

Hence,seven added to double a number = 2x+7

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Milli can invite 5 guests to her birthday party.
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What is the area of the pentagon shown below a.27 square feet b. 58.5 c.85.5 d.117
Sergio [31]

Answer:

Option B, Area of pentagon = 58.5 Square feet

Step-by-step explanation:

The remaining part of the question is attached as image

Solution

Area of pentagon has a triangle and a trapezoid

Area of triangle = 0.5 *base *height = 0.5*9 *3 = 13.5  square feet

Area of trapezoid = Area of rectangle – 2* area of smaller triangles

= 9 ft * 6ft – ( 2 * 0.5 * 6 ft * (9 ft – 6ft) /2

= 54 – (1*6*1.5)

Area of pentagon = 13.5 + 45 = 58.5 Square feet

Hence, option B is correct

3 0
2 years ago
The ____________ blank is the number that occurs most frequently in a group of numbers.
ioda

Answer:

mode

Step-by-step explanation:

mode is the number that has the highest occurrences in a set of numbers

4 0
1 year ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

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3 years ago
In right trapezoid MNPQ
AysviL [449]

Answer:

2

Step-by-step explanation:

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