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sweet-ann [11.9K]
3 years ago
5

Solve for r: C = 2 pi r. (1

Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

C/2pi = r

Step-by-step explanation:

C = 2 pi r

divide with 2 pi on both sides to solve for r

C/2pi = r

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2x - 4 &gt; 4<br> ...................
Veseljchak [2.6K]

Answer:

x>4

Step-by-step explanation:

8 0
3 years ago
Which graph represents the function f(x)=-|x|-2?
skad [1K]

Answer:

ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).

(0,−2)

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(−∞,∞)

Set-Builder Notation:  {x|x ∈ R}

For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.

 x     y

−2   −4

−1    −3

 0   −2

 1    −3

 2   −4

Step-by-step explanation:

5 0
3 years ago
Change Y - 4X = 0 to the slope-intercept form of the equation of a line.
Bingel [31]

Answer:

y=4x

Step-by-step explanation:

Add 4x to both sides to get y=mx+b

0 is y-intercept.

4x is the slope.

6 0
3 years ago
2/5 times ( -10)=?<br> ?=
Rudiy27

\frac{2}{5}  \times ( - 10)

2 \times  - 2

- 4

6 0
3 years ago
Read 2 more answers
What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


6 0
3 years ago
Read 2 more answers
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