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Alexus [3.1K]
3 years ago
16

What values of b satisfy 3(2b + 3)2 = 36?

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


bearhunter [10]3 years ago
4 0

Answer:

Everyone is simplifying too far. The answer is A. b = (-3 +- 2 square root 3) / 2

Step-by-step explanation:

+-square root 3 - 3/2 is correct but that is not one of the options.

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