Question

What values of b satisfy 3(2b + 3)2 = 36?

Answer 1

the correct question is

What values of b satisfy 3(2b+3)^2 = 36

we have

$3(2b+3)^2 = 36$

Divide both sides by $3$

$(2b+3)^2 = 12$

take the square root of both sides

$( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3$

$b1=\frac{\sqrt{12}}{2} -\frac{3}{2}$

$b1=\sqrt{3} -\frac{3}{2}$

$b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}$

$b2=-\sqrt{3} -\frac{3}{2}$

therefore

the answer is

the values of b are

$b1=\sqrt{3} -\frac{3}{2}$

$b2=-\sqrt{3} -\frac{3}{2}$

Answer 2

Answer:

Everyone is simplifying too far. The answer is A. b = (-3 +- 2 square root 3) / 2

Step-by-step explanation:

+-square root 3 - 3/2 is correct but that is not one of the options.