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aev [14]
3 years ago
13

The formula D= 393t + 5680 can be used to approximate rhe tital average credit card debt in a U.S. household (in dollars) t year

s after 1995. Use this formula to predict what the total average credit card debt will be in the year 2027
Mathematics
1 answer:
Schach [20]3 years ago
8 0
<span>In this problem the formula for average credit card debt is D=393t+5680 where t is years after 1995. To find the total average credit card debt in the year 2027, we must first find the difference in years between 2027 and 1995 to get our t value. To do this subtract 1995 from 2027: t= 2027 - 1995 = 32 years. Next, we plug in 32 for t into the equation and solve for D: D = (393)*(32) + 5680 = $18,256.</span>
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Draw and label an example of two parallel lines that are perpendicular to a third line.
lara31 [8.8K]
Euclid used a somewhat different parallel postulate in trying to avoid the notion of the infinite.  He observed that when two parallel lines are intersected by a third line, called a transversal, then if you measure two angles formed by these three lines, on the same side of the transversal and between the parallels, they will add to  (that is, they will be supplementary).  Such angles are called same-side interior angles<span>:</span>

7 0
2 years ago
F(1)=15<br> f(n)=f(n-1)*n<br> What does f(2) equal?
Arlecino [84]

Answer:

f(2) =30

Step-by-step explanation:

f(1)=15

f(n)=f(n-1)*n

Put in n=2

f(2)=f(2-1)*2

     = f(1) *2

      = 15*2

       =30

3 0
3 years ago
Read 2 more answers
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

3 0
3 years ago
HELP
lbvjy [14]
Y=9r, r=r

9r+r=30
10r=30
r=30/10
r=3(Red Sox)

yankee=9(3)=27
3 0
2 years ago
Read 2 more answers
Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
2 years ago
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