Is this graph a function or not a function
1 answer:
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The coordinates for the pre-image are P(1,3), Q(4,4), R(4,1), and S(1, -1).
The transformation is 4 units left, and 4 units down.
That means we must subtract 4 units to x-coordinates, and subtract 4 units from y-coordinates. So, the image has coordinates P'(-3,-1), Q'(0,0), R'(0, -3), and S'(-3, -5).
The image below shows the image and pre-image.
