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3 years ago

11

Given that QRST is a kite and that ST = TQ, find ST.

1 answer:

Debora [2.8K]3 years ago

8 0

Q/R = S/T as Q/T = R/S

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What's the ordered pair ?

nekit [7.7K]

The answer will be the set of points that contains a different x value for each point.

We clearly see that for ever point in terms of CHOICE C the value of x is different.

Answer: Choice C

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3 years ago

Keri is simplifying 5·10^−3.

11111nata11111 [884]

Answer:

1. D

2. A

Step-by-step explanation:

Q1. Kerry is simplifying $5\cdot 10^{-3}$

By the definition of negative powers,

$a^{-n}=\dfrac{1}{a^n}$

Hence,

$10^{-3}=\dfrac{1}{10^3}$

So, the first step in simplifying the expression is

$5\cdot 10^{-3}=5\cdot \dfrac{1}{10^3}$

Q2. Given the expression

$\dfrac{8}{10^{-2}}$

First, use the definition of negative powers:

$10^{-2}=\dfrac{1}{10^2}$

Thus,

$\dfrac{8}{10^-2}=\dfrac{8}{\frac{1}{10^2}}=8\cdot 10^2=8\cdot 100=800$

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3 years ago

A first-aid booth is located 3/4 of the distance from point A to point B. At what marker on the path is the first-aid booth loca

Anastaziya [24]

3/4*8= 24/4= 6 this is 3/4 the distance between point a and b

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2 years ago

Shelley read 40 business proposals between 6 am and 11 am. On average how many proposals did she read per hour

UkoKoshka [18]

Answer: 8 proposals per hour

Step-by-step explanation: 40/5 = 8

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2 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

svet-max [94.6K]

Here we will use the trial and error method.

We will try putting different values of x.

<h3 /><h3>1st of all</h3><h3>x=1</h3>

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}$

<h2>Now,</h2><h3>x=2</h3>

$\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}$

<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}$

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>

5 0

3 years ago